Draw the line that is parallel to y = 2x + 5 and passes through the point (2,3). Select the point through which the
graph passes.
C
D
A
E

point C (-1, -3)

Step-by-step explanation:

The line you are looking for already has two givens: m = 2 and it has coordinate (2,3) on it. You can plug these in to find the equation of the line and then see which of the 4 points it must pass through.

         3 = 2(2) + b

         -1 = b

         the line you are looking for is y = 2x - 1

First, you can rule out points D and B, because after a quick look, you can see that a line with a slope of 2 wouldn't come close to the point (2,3). Now you can choose between C (-1, -3) and A (-2, -3).

         Now you can plug in the points C and A into the equation of the line that was obtained in the first part of this answer.

         checking point A: -3 = 2(-2) - 1

                                        -3= -5

                                       not true, so now we check point C

         checking point C: -3 = 2(-1) - 1

                                       -3 = -2 - 1

                                       -3 = -3

                                       true, so the point must be C

I hope you did good

Step-by-step explanation:

I see that it's from an hour ago, I hope you did well <3

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!