1.Estimate the size of a crowd at a parade along a 1-mile section that is 8 feet deep on both sides. Assume 1 person for each 4.5 square feet. a.
46,900
b.
84,400
c.
18,700
d.
37,500
2.Estimate the size of a crowd at a parade along a 2-mile section that is 10 feet deep on both sides. Assume 1 person for each 4.5 square feet.
a.
46,900
b.
84,400
c.
18,700
d.
23,400
3.Estimate the size of a crowd at a parade along a 2-mile section that is 10 feet deep on both sides. Assume 1 person for each 2.5 square feet.
a.
84,500
b.
84,000
c.
126,700
d.
42,000
4.Estimate the size of a crowd at a concert where the area is 100 yards by 50 feet. Assume 1 person for each 2.5 square feet.
a.
12,000
b.
6,000
c.
2,000
d.
2,500

1)

c.

18,700

2)

a.

46,900

3)

a.

84,500

4)

a.

12,000

Step-by-step explanation:

1) 1 mile = 5280 ft.

Area of both sides = 5280 ft × 8 ft × 2 sides = 84480 ft²

Since 1 person for each 4.5 square feet, the ratio of one person to 1 square feet =

the size of a crowd = ≈ 18700

2) 1 mile = 5280 ft, therefore 2 mile = 10560 ft (5280 × 2)

Area of both sides = 10560 ft × 10 ft × 2 sides = 211200 ft²

Since 1 person for each 4.5 square feet, the ratio of one person to 1 square feet =

the size of a crowd = ≈ 46900

3) 1 mile = 5280 ft, therefore 2 mile = 10560 ft (5280 × 2)

Area of both sides = 10560 ft × 10 ft × 2 sides = 211200 ft²

Since 1 person for each 2.5 square feet, the ratio of one person to 1 square feet =

the size of a crowd = ≈ 84500

4) 1 yard = 3 ft, therefore 100 yard = 300 ft (100 × 3)

Area of both sides = 300 ft × 50 ft × 2 sides = 30000 ft²

Since 1 person for each 2.5 square feet, the ratio of one person to 1 square feet =

the size of a crowd =