A fence is to be built to enclose a rectangular area of "200" square feet. The fence along three sides is to be made of material that costs "5" dollars per foot, and the material for the fourth side costs 15 dollars per foot. Find the dimensions of the enclosure that is most economical to construct.

20 ft by 10 ft.

Step-by-step explanation:

Let the dimension of the rectangular enclosure be x ft by y ft

Perimeter, P(x,y)=2(x+y)=x+x+2y

Fencing material along three sides costs $5 per foot

Fencing material for the fourth side costs $15 per foot.

Therefore, Cost of Fencing=$(15x+5x+5y+5y)

C(x,y)=20x+10y

We can write the cost function as a function of one variable by substituting for y.

Recall: xy=200

Therefore:

To determine dimensions of the enclosure that is most economical to construct, we minimize C(x) by taking its derivative and solving for its critical points.

Recall that:

Therefore, the dimension of the enclosure that is most economical to construct is 20 ft by 10 ft.

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.