The altitude of the triangle ABC, segment DA, has been drawn. Derive a formula for the area of triangle BCA that depends on the measure of angle B along with side lengths a and c.

Triangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side B C forming a right angle. The length of C B is a, the length of C A is b, the length of A B is c, and the length of A D is h.

Area = One-half(base)(height)

Following this setup:

Area = One-halfah

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

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