A line passes through the point, (−8,7) and has a slope of −5/4. Please help...

5x + 4y + 12 = 0

Step-by-step explanation:

Start with the point-slope equation of a straight line:  y - k = m(x -  h):

Here we are given the point (h, k):  (-8, 7) and the slope m = -5/4.  Inserting this info into the equation give above, we get:        y - 7 = (-5/4)(x + 8).

We must put this equation into "standard form" Ax + By + C = 0.

Multiply all three terms by 4 to remove fractions:  4y - 28 = -5(x + 8), or

4y - 28 + 5x + 40 = 0

Rearranging these terms, we get 5x + 4y + 12 = 0, which is the desired equation in standard form.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it