The vertex form of the equation of a parabola is y= 3(x-4)2 +13. What is the
standard form of the equation?
- 4x +29
O A. y-*x -3x+21
O B. y=x2-
O C. y - 1x2 - 4x +21
OD. y = 2x2-3x+29
SIM
Help help please

ιт ιѕ 6 6/23

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт

ιт ωιℓℓ вєтнє fιяѕт ¢нσι¢є(α.)

convert the exponential equation to a logarithmic equation using the logarithm base (6) of the right side (36) equals the exponent (2).

ℓσg6(36)=2

нσρє ι ¢συℓ∂ нєℓρ уα

the area of a triangle is determined by the formula: base x height * 1/2

you'll need to assign a base to the triangle. based on the vertices given, the simplest base would be the line segment from (-2,1) to (2,1). the distance between any two numbers is found by just subtracting them. here, you should subtract the x values to find the distance of this side.

2 - (-2) = 4.

so the distance (aka the length of the base) is 4. the height of the triangle is the distance between the base and the highest point on the triangle which is (3,4). we should subtract the y values this time to find the height/distance.

4 - 1 = 3

so the height is 3.

base = 4

height = 3

hope this if needed hmu