The equation of a line tangent to f(x) at x-3 is given by Y=6x+8, what is the value of f'(x) ?

The equation of a line tangent to f(x) at = x - 3 is given by Y = 6x + 8

=> f'(x - 3) = 6x + 8

=> f(x - 3) = 3x^2 + 8x

=> f(x - 3) = 3(x^2 - 6x + 9) + 26(x - 3) + 51

=> f(x - 3) = 3(x - 3)^2 + 26(x - 3) + 51

=> f(x) = 3x^2 + 26x + 51

=> f'(x) = 6x + 26

Hope this helps!

:)

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.