Solve for x

khan academy solve similar triangles advanced

x = 10/3

Step-by-step explanation:

The question is incomplete without the diagram as this would enable us solve for x. Find attached the diagram used for solving the question.

We can tell from the question we are to compare two triangles drawn together (smaller one drawn in a bigger one) using similar triangles.

Using similar triangles to solve for x,

∆ABC = ∆ADE

∠CBA = ∠EDA = 90°

Let's relate the ratio of their corresponding sides.

(Adjacent/opposite) in ∆ABC

= (Adjacent/opposite) in ∆ADE

AB/CB = AD/ED

AB = 6

CB = 2

AD = AB + BD = 4+6 = 10

ED = x

6/2 = 10/x

3 = 10/x

3x = 10

x = 10/3

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