Imagine the center of the Ferris wheel the London Eye is located at (0, 0) on a coordinate grid, and the radius lies on the x-axis. Write an equation of a circle for your Ferris wheel, and sketch an image of what your Ferris wheel would look like on the grid.

Answer- (x-0)squared + (y-0)squared = 60squared

(x – 0)2 + (y – 0)2 = 3600

Step-by-step explanation:

The equation fo a circle is (x – h)<2 + (y – k)<2 = r<2. Since the center of the circle is located on the origin, the h and k value are 0 (h) and 0 (k). After plugging this into the previous equation, you get (x – 0)<2 + (y – 0)<2 = r<2. The radius of the London Eye is 60, so you then get (x – 0)<2 + (y – 0)<2 = 60<2. All that's left to do is simplify, and the equation ends as (x – 0)2 + (y – 0)2 = 3600.

60

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2