A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 1 meter, its length is 8 meters, and its top is 5 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8 m/s^2

9.94 * 10⁵ Joules

Step-by-step explanation:

The tank was not said to be at any certain level so we can assume that the tank is initially full.

The center of gravity is at the center of the tank.

The distance below ground = 5 + 1 = 6 meters

Mass of fuel = π * 673 * 1² * 8 = 16921.14 kg

Work done = weight * height

= 16921.14 * 9.8 * 6

= 9.94 * 10⁵ Joules

think the answer is 30 degrees. if not than it is 20 degrees. not 100% sure. let me know if it was right.

gill russ