On a coordinate plane, triangle J K L has points (negative 2, 1), (0, 3), and (2, negative 1). Reflect the figure over the line x = 0. The coordinate of J’ is . The coordinate of K’ is .

J'(2, 1)

K'(0, 3)

Step-by-step explanation:

On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.

If we reflect these points over the line x = 0 or y-axis, rule to be followed is

(x, y) → (-x, y)

Only sign of x coordinates get changed while y coordinates remain the same.

Following this rule coordinates of the images of J' and K' will be

J(-2, 1) → J'(2, 1)

and K(0, 3) → K'(0, 3)

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: