Question 2 (1 point)
The table represents the number of roses, b), remaining depends on the number of specialized bouquets created b.
To
0
4
240
6 8
216192
10
168
12
144
The equation Rb) - 288 - 12b models the function represented in the table. What are the restricted domain and range of the function?
The domain is all whole numbers from 0 to 12 inclusive. The range is all whole numbers from 0 to 240 inclusive,
The domain is all whole numbers from 0 to 24 inclusive. The range is all whole numbers from 0 to 288 inclusive
The domain is all whole numbers from 4 to 24 inclusive. The range is all whole numbers from 144 to 288 inclusive.
The domain is all whole numbers from 4 to 12 inclusive. The range is all whole numbers from 144 to 240 Inclusive.
Question 3 11 point
Phan is the tank of her car with gasoline before starting her road trio. The table below shows the amount of gas left in her tank as she drives.
Number of Hours vs. Amount Left in Tank
Number of Hours Spent
Driving (h)

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

x + 4/7

step-by-step explanation:

use cymath

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,