Find the area of the shaded region.

60+4.5pi

Step-by-step explanation:

6×10 obv + area of circle pi(r^2) and half that for a semi cirxle

9 π^2

Step-by-step explanation:

Let's just fined the area of the rectangle: Area= 2lw = A=60

Now, we know the diameter of the Spehre which is 10 -2 -2 = 6, the radius is half of that = 3

A=πr2 = A≈28.27

add A≈28.27 + 60 = 88.27 = 9 π^2≈88.82643

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6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.