Order the steps to solve the equation log3(x + 2) = log3(2x2 β 1) from 1 to 6.
0 = (2x β...
Mathematics, 05.05.2020 04:40 mpateltx
Order the steps to solve the equation log3(x + 2) = log3(2x2 β 1) from 1 to 6.
0 = (2x β 3)(x + 1)
0 = 2x2 β x β3
Potential solutions are β1 and 3
2
.
2x β 3 = 0 or x + 1 = 0
x + 2 = 2x2 β 1
3log3(x + 2) = 3log3(2x2 β 1)
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