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Mathematics, 05.05.2020 04:40 mpateltx

Order the steps to solve the equation log3(x + 2) = log3(2x2 βˆ’ 1) from 1 to 6.

0 = (2x βˆ’ 3)(x + 1)

0 = 2x2 βˆ’ x βˆ’3

Potential solutions are βˆ’1 and 3
2
.

2x βˆ’ 3 = 0 or x + 1 = 0

x + 2 = 2x2 βˆ’ 1

3log3(x + 2) = 3log3(2x2 βˆ’ 1)

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Order the steps to solve the equation log3(x + 2) = log3(2x2 βˆ’ 1) from 1 to 6.

0 = (2x βˆ’...
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