Magdeline wants to know if the number of words on a page in her art book is generally more than the number of words on a page in her science book. She takes a random sample of 25 pages in each book and then calculates the mean, median, and mean absolute deviation for the 25 samples of each book.

Book Mean Median Mean Absolute Deviation
Art 68.7 50 15.4
Science 54.2 55 7.9

She claims that because the mean number of words on each page in the art book is greater than the mean number of words on each page in the science book, the art book has more words per page. Based on the data, is this a valid inference?

Step-by-step explanation:

To know on  which book, number of words is more between, Computer Science and Math

Magdeline selects 25 pages from each book, then Calculates Mean, Median, Mean Absolute Deviation of number of words on each page.

Book                Mean    Median     Mean Absolute Deviation

Computer science 48.7            40                   9.4

Math                  34.2         45                      1.9

Observing what Magdeline has Done,

Mean is Sum of words on each page of 25 pages divided by 25.

1. Mean of Computer Science book is more than mean number of words on pages of math book.

2.And, Median means , computer science book has more pages which contains 40 words ,and Math book  has more pages which contain 45 words.

3.Now,Coming to Mean Absolute Deviation, which measures the Variability from Mean.

In computer science book ,there is more Variability that is, 9.4 and 1.9 in math book.

So, just by claiming, that because the mean number of words on each page in the computer science book is greater than the mean number of words on each page in the math book, the computer science book has more words per page appears invalid Inference, because variability from mean in computer science book is more than variability from mean in Math book because Mean Absolute Deviation measures Variability fro mean.

Option D:  No, because there is a lot of variability in the computer science book data

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delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

y=20x

: )

hope this