Rectangle A, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0), B(6, 0), C(6, 7), and D(2, 7)

The dimensions of the rectangle would be (6-2) x (7-0) = 4 x 7

That makes the area (4)(7) = 28.

That makes the perimeter (7+4)(2) = 22

That makes the diagonal sqrt((7^2)+(4^2)) = sqrt(49+16) = sqrt(65)

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

u