A medical school claims that more than 28% of its students plan to go into general practice. It is found that among a random sample of 130 of the school's students, 32% of them plan to go into general practice. Find the P-value for a test of the school's claim.

a. 0.1635
b. 0.3461
c. 0.1539
d. 0.3078

And the best option would be:

c. 0.1539

Step-by-step explanation:

Data given and notation

n=130 represent the random sample taken

estimated proportion of students who plan to go into general practice

is the value that we want to test

z would represent the statistic (variable of interest)

represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.28:  

Null hypothesis:  

Alternative hypothesis:  

When we conduct a proportion test so we need to use the z statistic, and the is given by:  

(1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Statistical decision  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

And the best option would be:

c. 0.1539

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.