A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. Which expression would determine the probability that both digits are even?

A - P(both even) = (4P1)(3P1)/9P2

B - P(both even) = (4C1)(3C1)/9C2

C - P(both even) = (5P1)(4P1)/9P2

D - P(both even) = (5C1)(4C1)/9C2

addition

step-by-step explanation:

dont't really have enough info here but its likely

sss for the three sides being congruent ( its stands for side side side)

or

sas   for side angle side.   so a side is congruent and and angle and a side

answer: chelsea has 55 brushes

step-by-step explanation:

5 x 11 = 55

5 + 55 = 60