A support wire is tied diagonally from the middle of a tree to a stake on the ground. The length of the wire is 10 ft and the angle of
elevation from the stake is 55". Approximately how high on the tree is the connection point of the wire?

8.2 ft

.Step-by-step explanation:

Sketch this situation.  Label the 55° angle.  The adjacent side is the distance from the stake to the bottom center of the tree.  The opposite side is the distance from the ground to the connection point of the wire on the tree.  The wire length represents the hypotenuse of this triangle.  We want to find the length of the side opposite the 55° angle.  Thus, we write

sin 55° = (opposite side)/(hypotenuse), or

(hypotenuse)(sin 55°) = (10 ft)(0.819) = 8.2 ft

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

where's the diagram?

step-by-step explanation: