Acar moves from postion 50m south of the library to new position 250m north of the library this movement takes 15 seconds what is the velocity of the car

A car moves from position 50m south of the library to new position 250m north of the library this movement takes 15 seconds what is the velocity of the car

Step-by-step explanation:

The equation is displacement/time = (250 + 50) m/ 15 s = 20m/s.

The answer is: 20m/s.

0 is its x and y coordinate

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°