Of 100 students, 32 are taking Calculus, 29 are taking French, and 13 are taking both Calculus and French, if a student is picked at random
what is the probability that the student is taking Calculus or French?
(Reduce fraction to lowest form)

Step-by-step explanation:

The total number of students = 100

Let A represents calculus and B represents French

The no of students taking calculus = 32

The no of students taking French = 29

The no of students taking calculus and french = 13

the probability that the student is taking Calculus or French = ?

P (AUB) = P(A) + P(B) - P(A∩B)

= + -

=

Reducing to lowest fraction,  it becomes

The probability that the student is taking Calculus or French =  

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540