Maximum points and Brainliest. Qu. Work out the isosceles triangle angle AED and show workings.

40 degrees.

Step-by-step explanation:

m < ADC = 110 degrees  (The opposite angles of a parallelogram are equal).

m <  ADE = 180 - 110 = 70 degrees  ( adjacent angles are supplementary).

Now triangle ADE is isosceles so the base angles are equal, therefore:

m < AED = 180 - 2(70) = 40 degrees.

40 degrees

Step-by-step explanation:

Opposite angles in a parallelogram are congruent.

We know that <B is 110 degrees, and it’s opposite angle is <ADC. So <ADC must also be 110 degrees.

<ADC and <ADE are on a straight line, and they are supplementary, or add to 180 degrees

<ADC + <ADE =180

110 + <ADE =180

Subtract 110 from both sides

<ADE=70

We know the triangle is isosceles, so <DAE must also be 70 degrees

The angles in a triangle must add to 180 degrees.

<DAE + <ADE + <AED = 180

70 + 70 + <AED =180

140 + < AED =180

Subtract 140 from both sides

<AED=40

21

jk it's 20

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: