Immanuel was able to save 130 coins in 25- and 5-centavo denominations in a coco shell. if the AMOUNT OF THE SAVINGS IS 20.50 Pesos, how many of each kind are there?

70    25 centavo pieces

60    5 centavo pieces

Step-by-step explanation:

Let x = number of 25 centavo pieces

y = number of centavo pieces

The total number of pieces is 130

x+y = 130

The total amount is 20.50

.25x+.05y =20.50

Solve for y

x+y = 130

y = 130-x

Substitute into

.25x+.05y =20.50

.25x +.05(130-x) = 20.50

Distribute

.25x +6.5-.05x = 20.50

Combine like terms

.2x +6.5 = 20.50

Subtract 6.5 from each side

.2x +6.5-6.5 = 20.5-6.5

.2x =14

Divide each side by .2

.2x/.2 = 14/.2

x = 70

Now we can solve for y

y = 130-x

y = 130-70

y = 60

25-centavo: 70 coins

5-centavo: 60 coins

Step-by-step explanation:

x + y = 130

25x + 5y = 2050

5x + y = 410

y = 410 - 5x

x + 410 - 5x = 130

4x = 280

x = 70

y = 410 - 5(70) = 60

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !