O (x, y) = (xβ8, y-3)
* (x, y) = (x-3, y + 3)
Mathematics, 16.04.2020 23:19 mitetwojr
Which rule describes the translation?
O (x, y) = (xβ8, y-3)
* (x, y) = (x-3, y + 3)
O (x, y) + (x+8, y-3)
O (x, y) + (x + 3, 7 + 8)
Answers: 3
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You know the right answer?
Which rule describes the translation?
O (x, y) = (xβ8, y-3)
* (x, y) = (x-3, y + 3)
O (x, y) = (xβ8, y-3)
* (x, y) = (x-3, y + 3)
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