Find mu if mu equals Summation from nothing to nothing [x times Upper P (x )]. Then, find sigma if sigma squared equals Summation from nothing to nothing [x squared times Upper P (x )]minus mu squared.

mu = x√P(x) - £

£ = x√P(x) - xP(x)

Step-by-step explanation:

We have two equations there. Laying them simultaneously, we can derive the formula for "mu" and sigma. Let sigma be "£"

Equation 1

mu = £[xP(x)]

Equation 2

£^2 = x^2 P(x) - (mu)^2

Since we have sigma raised to power 2 (that is sigma square), we find sigma by square rooting the whole equation.

Hence sigma is equal to

[x√P(x) - mu] ...(3)

Since mu = xP(x), we substitute this into equation (3) to get

Sigma = x√P(x) - xP(x)

mu = x√P(x) - £

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

207/8 is the right