An object is launched from a platform. It's height is meters is modeled by: h(x)= -5(x+1)(x-9) where x represents the time in schools after the launch. How many seconds after launch will the object hit the ground

9 seconds

Step-by-step explanation:

When the object hit the ground,

Height h = 0

Therefore,

h(x)= -5(x+1)(x-9) = 0

0 = -5(x+1)(x-9)

Open the bracket

0 = (-5x - 5)( x - 9)

0 = -5x^2 + 45x - 5x + 45

0 = -5x^2 + 40x + 45

Divide all by -5

0 = x^2 - 8x - 9

Factorizing the equation gives

(x + 1)(x- 9)

x = -1 or 9

Since Time can't be negative

Therefore, the time seconds after launch the object will hit the ground is 9 seconds

i pretty sure it is

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .