Since slope is calculated using the formula m= 2 11 the
X2 - X1
slope of both lines is equivalent to L . It is given
that the lines are parallel, and we calculated that the slopes
are the same. Therefore, parallel lines have the same
slopes.
A. V-Z/ W-X

B. W-X/V-Z

C. V-Z+B/X-Z+B

D. W-X+A/V-Z+B

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.