'find the highest common factor of 32, 48 and 72. show your working'
asap < 3

HCF(32,48,72) = 8

Step-by-step explanation:

We have ,

32 = 2×2×2×2×2 =

48 = 2×2×2×2×3 = 2⁴×3¹

72 = 2×2×2×3×3 = 2³×3²

Now,

HCF(32,48,72) = 2³ = 8

/* Product of the smallest power of each common prime factors of the numbers */

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.