Find the discriminant of the quadratic equation x2 + 10x + 24 = 0 and use it to determine the number and types of solutions.

b2 − 4ac

196; Two real solutions
196; One real solution
4; Two real solutions
4; Two nonreal solutions

4; two solutions

Step-by-step explanation:

b^2-4(a)(c)

100^2-4(1)(24)

-4(1)(24)=-96

-96+100=4.

And four is not negative therefore there are two solutions.

The answer is 4; two real solutions

Step-by-step explanation:

after solving the question using the formula b^2-4ac I've gotten 4>0 if the formula b^2-4ac>0 then there would be 2 real solutions, the parabola crosses the x-axis twice. hope this helps, please tell me if I was right. :)

y + 11 = (1/4)(x + 16)

step-by-step explanation: