What are the values that make x^2 + bx + 64 a perfect square?

b = ±16

Step-by-step explanation:

Normally to find the number we add to make it a perfect square

We take the coefficient of x

b

Divide by 2

b/2

Then square it

(b/2) ^2

In this case, we are adding 64

(b/2) ^2 = 64

Take the square root of each side

sqrt((b/2) ^2) = sqrt(64)

b/2 = ±8

Multiply each side by 2

b/2*2 =  ±8 *2

b = ±16

16, -16

Step-by-step explanation:

For a perfect square,

B² - 4AC = 0

b² - 4(1)(64) = 0

b² = 256

b = +/- 16

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

c

step-by-step explanation: