A bag of M&M's has 4 red, 2 green, 3 blue, and 5 yellow M&M's. Suppose you randomly select two
M&M's from the bag one at a time with replacing the first M&M.
Let A = first M&M is blue and B = second M&M is green.
Find the following probabilities. (Write your answers as fractions.)
a) P(A) =
b) P(
BA) =
C) P(A and B) =
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step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

8+10

step-by-step explanation:

you multiply 4 by 2 and 5 by 2