Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 11 ft high

The height is increasing at the rate of 0.42 ft/min

Step-by-step explanation:

Given that:

The diameter = height

and

diameter d = 2 r

2 r = h

r =

The volume of the cone formed = v

v ⇒ = 40 ft³/ min

at h = 11 ft high

Hence, the height of the pile was increasing at the rate of 0.42 ft/min

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5