The radius of the cone is 1.25 inches, and it’s height is 2.75 inches. if the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice?

the volume of the cone that can be filled with flavored ice is .

Step-by-step explanation:

Here we have , the radius of the cone is 1.25 inches, and it’s height is 2.75 inches. if the diameter of the bubble gum ball is 0.5 inches, We need to find what is the closest approximation of the volume of the cone that can be filled with flavored ice. Let's find out:

We know that , Volume of cone is :

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Putting values of r=1.25 inches & h= 2.75 inches we get :

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Now , Volume of sphere is :

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Putting r = 0.25 inches( D = r/2 = 0.5/2=0.25 ) we get :

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So , volume of the cone that can be filled with flavored ice:

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Therefore , the volume of the cone that can be filled with flavored ice is .

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

won't that be plagrisim thought?

step-by-step explanation: