Using the letters in the word MATH, how many 4 letter combinations can you make?

322490 Can you help me out with my question

Step-by-step explanation:

24

Step-by-step explanation:

While not all of these words would be real words, there are still 24 different combinations of 4 letters you can make.

Basically think like this:

There are 4 options you have when you chose the first letter right? You can use any of the 4 letters for the first letter.

This leaves you with exactly 3 ways to choose the second letter, which makes 12 ways to choose the first 2 letters.

When we get to the third letter, you have 2 more ways to choose, which means we can multiply 12 by 2 to get the combinations of the first 3 letters

And for the last letter of course, there is only one option for it, so the final product is:

4*3*2*1 = 24 letters

*Note*: If you use letters more than once, the possible combinations number would have to be 256 or 4^4

Thank me later :)

(or just mark as brainliest)

  b:   ∠x = 28.6°, ∠y = 31.2°, ∠z = 120.2°

step-by-step explanation:

this is one of those questions where "test taking skill" is all you need. the only answer that has angles that sum to 180° is the one shown above. the remaining choices do not describe the angles of a triangle.

if you want to do more work than simply adding the offered numbers, you can also check them against the law of sines. it should be true that

  x/sin(x) = y/sin(y) = z/sin(z)

and all of these ratios must be greater than 15, the longest side length.

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if you want to solve the triangle from scratch, i'd suggest solving for the largest angle using the law of cosines.

  z² = x² +y² -2xy·cos(z)

  z = arccos((x² +y² -z²)/(2xy)) = arccos(-75.11/149.4) = 120.182°

now you can find y from the law of sines

  y = arcsin(y/z·sin(z)) = 31.242°