Parallelogram ABCD is rotated 45° counterclockwise using the origin as the center of rotation. On a coordinate plane, parallelogram A B C D has points (2, 5), (2, 2), (negative 1, negative 1), (negative 1, 2). Which graph shows the image of ABCD? On a coordinate plane, parallelogram A prime B prime C prime D prime has points (negative 2, 5), (0, 3), (0, negative 1.2), (negative 2, 1). On a coordinate plane, parallelogram A prime B prime C prime D prime has points (negative 2, 5), (negative 2, 1), (0, negative 1), (0, 3). On a coordinate plane, parallelogram A prime B prime C prime D prime has points (5, 2), (3, 0), (negative 1.5, 0), (0.5, 2). On a coordinate plane, parallelogram A prime B prime C prime D prime has points (5, 2), (1, 2), (negative 1.5, 0), (2.8, 0).

9514 1404 393

  A.  On a coordinate plane, parallelogram A'B'C'D' has points (-2, 5), (0, 3), (0, -1.2), (-2, 1)

Step-by-step explanation:

None of the choices are very good matches to the actual coordinates. Rounded to tenths, they should be ...

  A'(-2.1, 5.0), B'(0, 2.8), C'(0, -1.4), D'(-2.1, 0.7)

The closest match is choice A.

_____

The transformation is ...

  (x, y) ⇒ (0.71x -0.71y, 0.71x +0.71y)

where 0.71 is an approximation of √2/2.

65

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.