In a recent poll, 44% of survey respondents said that, if they only had one child, they would prefer the child to be a boy. Suppose you conducted a survey of 150 randomly selected students on your campus and find that 71 of them would prefer a boy.
(a) Use the normal approximation to the binomial to approximate the probability that, in a random sample of 150 students, at least 71 would prefer a boy, assuming the true percentage is 44%.
(b) Does this result contradict the poll? Explain.

a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47

b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted

Step-by-step explanation:

If 71 out of 150 prefer boy child

The probability that the 71 will prefer boy child is

= 71/150

The actual percentage is

(71/150)*100%

= 47.33%

This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.

the square root of what number? if you add that, then someone will probably answer the question.