Michael's dad is 30 years of age. He is 2 years more than four times Michaels age m. Write and solve a two-step equation to determine Michaels age. Use x as the variable

The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.

Step-by-step explanation:

In order to solve this problem we will attribute variables to the ages of Michael and his father. For his father age we will attribute a variable called "f" and for Michael's age we will attribute a variable called "x". The first information that the problem gives us is that Michael's dad is 30 years of age, so we have:

f = 30

Then the problem states that the age of the father is 2 years "more" than four "times" Michaels age. The "more" implies a sum and the "times" implies a product, so we have:

f = 2 + 4*x

We can now find Michael's age, for that we need to isolate the "x" variable. We have:

f - 2 = 4*x

4*x = f - 2

x = (f-2)/4

x = (30 - 2)/4 = 7 years

The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.

Michael's age is 7 years

Step-by-step explanation:

Let's call Michael's dad age by Y, and Michael age by X

if Michael's dad is 2 years more than four times Michaels age, we can put this information as an equation:

Y = 2 + 4*X

Then, we solve this equation (find the value of X) using the value Y = 30:

30 = 2 + 4*X

step 1: subtract 2 in both sides:

28 = 4*X

step 2: divide both sides by 4:

X = 7

Michael's age is 7 years

answer: y=0 if that is what u r looking for

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: