A standard six-sided die is rolled $6$ times. You are told that among the rolls, there was one $1,$ two $2$'s, and three $3$'s. How many possible sequences of rolls could there have been? (For example, $3,2,3,1,3,2$ is one possible sequence.)

There are 6*5*4 = 120 ways to choose the positions of the 3's.  Then there are 3 ways to choose the position of the 1, and the remaining rolls must be 2, so there are 120*3 = 360 possible sequences.

okay so 15.15 *()5: +5/6

step-by-step explanation:

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.