What is the surface area of this design?
A.150in2
B.197in2
C.210in2
D.127in2

197 in ^2 (answer B of the list)

Step-by-step explanation:

Notice that this figure has a total of 6 faces, four of which are rectangles (whose area is calculated as "base times height") and two trapezoids (whose area is (B+b)H/2 ).

The total surface area is therefore the addition of these six areas:

Rectangles:

5 in x 5 in = 25 in^2

5 in x 5 in = 25 in^2

5 in x 6.4 in = 32 in^2

9 in x 5 in = 45 in^2

Trapezoids:

Two of equal dimensions: B = 9 in, b = 5 in, H = 5 in

2 * (9 in + 5 in) 5 in /2 = 70 in^2

Which gives a total of  (25 + 25 + 32+45 + 70) in^2 = 197 in^2

This agrees with answer B of he provided list.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!