Mathematics, 31.03.2020 02:58 soccergirly7588

Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are 18 sophomores, 12 juniors and 10 seniors who are members of the student senate. In how many ways can the governance committee be selected, if it must be made up of 2 sophomores, 2 juniors and 3 seniors

Answers: 3

Show answers

Answers

Answer from: kfloyd6046

The governance committee can be selected in 29,082,240 ways.

Supposing that the members of a student governance committee will be selected from the 40 members of the student senate, and there are 18 sophomores, 12 juniors and 10 seniors who are members of the student senate, to determine in how many ways can the governance committee be selected, if it must be made up of 2 sophomores, 2 juniors and 3 seniors, the following calculation must be performed:

The number of options required by the students who have the possibility of occupying each position must be multiplied. 18 x 17 x 12 x 11 x 10 x 9 x 8 = X 306 x 132 x 720 = X 29,082,240 = X

Therefore, the governance committee can be selected in 29,082,240 ways.

Learn more in link

Answer from: teresaduggan1433

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select k items from n distinct items.

The formula is:

${n\choose k}=\frac{n!}{k!(n-k)!}$

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153$

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66$

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120$

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = ${18\choose 2}\times {12\choose 2}\times {10\choose 3}$

$=153\times 66\times 120\\=1211760$

Thus, the total number of ways to form a student governance committee is 1,211,760.

Suppose that the members of a student governance committee will be selected from the 40 members of t

Answer from: Quest

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

Answer from: Quest

answer: bea's uncle is 25 years old.

step-by-step explanation:

given the equation $3x- 15= 60$ , we can say that the variable "x" represents the age of bea's uncle. then to find his age, we need to solve for "x":

we must add 15 to both sides of the equation:

$3x- 15+(15)= 60+(15)\\3x=75$

now we need to divide both sides of the equation by 3:

$\frac{3x}{3}=\frac{75}{3}\\\\x=25$

therefore, we can conclude that bea's uncle is 25 years old.

Another question on Mathematics

Mathematics, 21.06.2019 18:00

Marla bought a book for $12.95, a binder for $3.49, and a backpack for $44.99. the sales tax rate is 6%. find the amount of tax and the total she paid for these items

Answers: 3

Answer

Mathematics, 21.06.2019 20:00

The two cylinders are similar. if the ratio of their surface areas is 9/1.44 find the volume of each cylinder. round your answer to the nearest hundredth. a. small cylinder: 152.00 m3 large cylinder: 950.02 m3 b. small cylinder: 972.14 m3 large cylinder: 12,924.24 m3 c. small cylinder: 851.22 m3 large cylinder: 13,300.25 m3 d. small cylinder: 682.95 m3 large cylinder: 13,539.68 m3

Answers: 2

Answer

Mathematics, 21.06.2019 20:30

Acircle has a circumference of 7.850 units. what is its radius?

Answers: 2

Answer

Mathematics, 22.06.2019 01:00

1) your friend taylor missed class today and needs some identifying solutions of systems. explain to taylor where to find the solution(s) of any system using its graph 2)taylor graphs the following in desmos and decides that f(x) = g(x) at x = 0, x = 1, & x = 3. f(x) = 2x+1g(x) = 2x2+1 provide taylor some feedback that explains which part of the answer was incorrect and why.

Answers: 1

Answer

You know the right answer?

Suppose that the members of a student governance committee will be selected from the 40 members of t...

Questions

Mathematics, 14.01.2020 03:31

There are 24 markers in 2 boxes of markers. which of the following expresses the ratio of markers to boxes?...