Mr. and Mrs. Jones live in a neighborhood where the mean family income is $45,000 with a standard deviation of $9,000. Mr. and Mrs. Smith live in a neighborhood where the mean is $100,000 and the standard deviation is $30,000. What is the relative dispersion of the family incomes in the two neighborhoods

Jones(20%), Smiths(30%)

Step-by-step explanation:

The relative dispersion of a data set is the ratio of its standard deviation to its arithmetic mean.

Mr. and Mrs. Jones' neighborhood mean family income is $45,000 with a standard deviation of $9,000.

Their Relative Dispersion is given as:

Standard Deviation: Mean

9000:45000

1:5

Expressed as a Percentage: (1/5)x100=20%

The Relative Dispersion of the family incomes in Mr. and Mrs. Jones' neighborhood is 20%

Mr. and Mrs. Smith's neighborhood mean family income is $100,000 and the standard deviation is $30,000.

Their Relative Dispersion is given as:

Standard Deviation: Mean

30000:100000

3:10

Expressed as a Percentage: (3/10)x100=30%

The Relative Dispersion of the family incomes in Mr. and Mrs. Smith's neighborhood is 30%

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

it is c, trust i got your back lol

step-by-step explanation: