I need help with exponents I can’t have negative exponents

Step-by-step explanation:

1/8x^-2y^-6

From the law of indices a^-1=1/a^1

Adopting these

(8x^-2y^-6)^-1

8^-1(x^-2)^-1(y^-6)^-1

8 = 2x2x2=2^3

(2^3)^-1(x^-2)^-1(y^-6)^-1

(2^-3)(x^-2-1)(y^-6-1)

(2^-3)(x^-3)(y^-7)

(3×)^-3y^4/-x^2y^-6

3^-3x^-3y^4/-x^2y^-6

From the law of indices / division means - subtraction

3^-3x^-3y^4/-x^2y^-6 = 3^-3x^-3^-2y^4^-6= 3^-3x^-5y^4+(-6)

3^-3x^-5y^-2

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|