The question is
Complete the lateral Surface area of the cylinder and prism. Explain how u found the lateral surface area for each

The lateral Surface area of the cylinder is 162.2 cm².

The lateral Surface area of the triangular prism is 226.6 cm².

Step-by-step explanation:

To find the lateral Surface area of the cylinder :

The given information are,

⇒ r = 4.2 ÷ by 2

⇒ r = 2.1 cm

∴ The radius is 2.1 cm

The lateral Surface area of the cylinder = 2πrh

⇒ 2 × π × 2.1 × 12.3

⇒ 51.66 π

We know the default value of π is 3.14

⇒ 51.66 × 3.14

⇒ 162.2 cm²

To find the lateral Surface area of the prism :

The given information are,

The lateral Surface area of the triangular prism = (b1+b2+b3)×h

⇒ (8+8+6) × 10.3

⇒ 22 × 10.3

⇒ 226.6 cm²

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)