Solve the system of linear equations.

y = x + 3

y = 2x - 2

x=5, y=8

Step-by-step explanation:

Since both equations equal y, we can set them equal

y = x + 3

y = 2x - 2

x+3 = 2x-2

Subtract x from each side

x-x+3 = 2x-x-2

3 = x-2

Add 2 to each side

3+2= x-2+2

5 =x

Now we need to find y

y =x+3

y=5+3

y=8

x = 5

y = 8

Step-by-step explanation:

to solve the linear system of equation , we would say that let

y = x + 3 equation 1  

y = 2x - 2 equation 2

substitute for equation 1 into equation 2

we have

x + 3 = 2x -2

collect the like terms

x + 3 + 2 = 2x

x + 5 = 2x

5 = 2x -x

5 = x

x = 5

substitute for the value of x = 5 in equation 2

y = 2x - 2 equation 2

y = 2(5) - 2

y = 10 - 2

y = 8

Therefore the value of x and y in the linear equation is 5 and 8 respectively

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8