Write a vector equation of the line that passes through p(–1 6) and is parallel to a = (3, -1).
A. (x+7, y+8) = t(5, 1)
B. (x-5, y-14) = t(8, 5)
C. (x+1, y-6) = t(3, -1)
D. (x+14, y+13) = t(-1, 8)
HELP FAST.

C

Step-by-step explanation:

(x,y) = p + t(a)

(x,y) = (-1,6) + t(3,-1)

(x,y) - (-1,6) = t(3,-1)

(x + 1, y - 6) = t(3, -1)

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation: