According to the National Postsecondary Student Aid Study conducted by the U. S. Department of Education in 2008, 62% of graduates from public universities had student loans. We randomly select 50 students at a time. Flag this Question Question 15 pts What is the mean of the distribution of sampling proportions? Do not round, and enter your answer as a proportion (decimal number) not a percentage. Flag this Question Question 25 pts What is the standard error for the distribution of sampling proportions? If necessary, round to three decimal places.

The mean of the sampling proportions is 0.62.

The standard error for the distribution of sampling proportions is 0.069.

Step-by-step explanation:

The proportion of graduates from public universities that had student loans is p=0.62.

The sampling distribution of the proportions, if the sample are of size n=50, has the following parameters:

The mean of the sampling proportions is 0.62.

The standard error for the distribution of sampling proportions is 0.069.

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look up a corrdinate plane and do what the thingy says and boom

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2