Suppose an eruptive prominence rises at a speed of 150 km/s. if it does not change speed, how far from the photosphere will it extend after 3 hours? how does this distance compare with the diameter of earth?

127 times

Explanation:

v = speed of eruptive prominence = 150 km/s = 150,000 m/s

t = time interval = 3 hours = 3 x 60 x 60 sec = 10800 sec

d = distance traveled by photosphere

Distance traveled is given as

d = v t

d = (150,000) (10800)

d = 1.62 x 10⁹ m

d = 1.62 x 10⁶ km

D = diameter of earth = 12742 km

n = number of times the distance traveled by eruptive prominence

using the equation

d = n D

1.62 x 10⁶ = n (12742)

n = 127 times

im guessing the west of station b