A particle moves so that r(t) = ati + b sin atj. Show that the magnitude of the acceleration of the particle is proportional to its distance from the x-axis.

Step-by-step explanation:

Given

Position of particle is

i.e. distance from x axis is

Distance from y axis at

velocity is given by

Similarly acceleration is given by

Magnitude of acceleration is

From 1 and 2 we can see that

Magnitude of acceleration is proportional to distance from x axis

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42