Mathematics, 15.06.2021 02:30 Jgarciar6841

1. A merchant sets the selling price of an article 40% above what it cost him. Then, seeing it did not sell, he decided to reduce the figure by 15%. The final selling price was $8.65. What did the article originally cost?

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Answer from: neariah24

7.27 dollars

Work Shown:

x = original cost (in dollars)

1.40x = increasing the cost by 40%

0.85*1.40x = decreasing the previous cost (1.40x) by 15%

Notice how a decrease of 15% means you pay the remaining 85% of the price, which is where the 0.85 comes from.

The expression 0.85*1.40x simplifies to 1.19x after multiplying the 0.85 and 1.40

The expression 1.19x is the final cost after the increase of 40% and the decrease of 15%

Set this equal to 8.65 and solve for x

1.19x = 8.65

x = 8.65/1.19

x = 7.2689075630252 which is approximate

x = 7.27 dollars

Let's check the answer

x = 7.27

1.40x = 1.40*7.27 = 10.178 = 10.18

After an increase of 40%, the cost is now $10.18

Now decrease it by 15%

discount = 15% of 10.18 = 0.15*10.18 = 1.527 = 1.53

The customer saves $1.53 and the final price is 10.18-1.53 = 8.65

So everything works out as we expect. The answer is confirmed.

Answer from: Quest

Ithink ghe answer to this question is b just trying to others
Find the perimeter of the shape below a- 7.4 units b- 8.9 units c- 11.2 units d- 13.6 units

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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1. A merchant sets the selling price of an article 40% above what it cost him. Then, seeing it did n...

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