Triangle ABC has vertices A(5,6) B(6,-3), and C(7,2). T<-2,3> (triangle ABC= triangle A'B'C'). What are the coordinates of the vertices of triangle A'B'C'?

The equivalent vertices of the triangle A'B'C' will be (3, 9), B'(4, 0), and C'(5, 5)

Given the vertices of a triangle ABC with the vertices  A(5,6) B(6,-3), and C(7,2).

If the coordinate is translated 2 units to the left and 3 units up, the resulting coordinates of the triangle will be expressed as;

A' = (5 - 2, 6 + 3) = (3, 9)

B' = (6 - 2, -3 + 3) = (4, 0)

C' = (7 - 2, 2 + 3) = (5, 5)

Hence the equivalent vertices of the triangle A'B'C' will be (3, 9), B'(4, 0), and C'(5, 5)

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A': (3,9)

B': (4,0)

C': (5,5)

Step-by-step explanation:

A': (5-2,6+3) = (3,9)

B': (6-2,-3+3) = (4,0)

C': (7-2,2+3) = (5,5)